HELP NEEDED

1 answer:

3 0

Part A: Find (h + t)(x). Show your work.
h(x) = 5x − 2 and t(x) = 4x + 6
so
(h + t)(x) = 5x − 2 + 4x + 6
(h + t)(x) = 9x +4

Part B: Find (h ⋅ t)(x). Show your work.
h(x) = 5x − 2 and t(x) = 4x + 6
so
(h ⋅ t)(x) = (5x − 2) (4x + 6)
(h ⋅ t)(x) = 20x^2 + 30x - 8x - 12
(h ⋅ t)(x) = 20x^2 + 22x - 12

Part C: Find h[t(x)]. Show your work.
h(x) = 5x − 2 and t(x) = 4x + 6
so
h[t(x)] = 5(4x + 6) − 2
h[t(x)] = 20x + 30 - 2
h[t(x)] = 20x + 28

hope all help.

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Step-by-step explanation:

Given : Suppose a flare is shot from the top of a 120 foot building at a speed of 160 feet per second. The equation $h =- 16t^2+ 160t + 120$ models the h height at t seconds of the flare.