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telo118 [61]
3 years ago
5

What is the range of y = –5sin(x)?

Mathematics
2 answers:
sergejj [24]3 years ago
4 0

Answer:

-5\leq y\leq5  is the required range.

Step-by-step explanation:

We have been given a function:

y=-5sin(x)

The range of sin x is -1\leq sinx\leq1

multiply -5 in each term of the above equation.

-1(-5)\geq -5sinx\geq-5

\Rightarrow 5\geq -5sinx\geq-5

Hence, the required range is:

-5\leq -5sinx\leq5

replace -5sinx by y so, we get:

-5\leq y\leq5


matrenka [14]3 years ago
3 0
[-5, 5] the Y value has a minimum of -5 and max of 5 so that is what your range is!
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---------------------

Therefore, since L = 8W <u>,</u> <u>L = 40 yards.   W = 5 yards</u> for the rectangle.

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--------------------------

Check:

Do a rectangle of 40' x 5' plus a square of 5' x 5' have a total combined area of 225 yards^2?

40yd x 5yd + 5yd x 5yd = 225 yards^2?

200 yd^2 + 25 yd^2 = 225 yards^2?

YES

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