A * b = 30
a - b = 1
a + b = 11
take ur last 2 equations, and add them
a - b = 1
a + b = 11
--------------add
2a = 12
a = 12/2
a = 6
now its just a matter of subbing
a + b = 11
6 + b = 11
b = 11 - 6
b = 5
so a = 6 and b = 5...whose product is 30, whose difference is 1, and whose sum is 11.
Answer:
2100
Step-by-step explanation:
In how many ways can a group of 10 people be divided into three groups consisting of 2,3, and 5 people?
First, you need to choose 4 people to fill the first group.
The number of ways is (104) which equals to 210.
Then, pick 3 more people out of the remaining 6 to be in the second group. And then, pick 3 more out of the remaining 3.
However, we need to divide it by 2, since we don’t really care on the order of selection of group.
(63)(33)/2=10
So, there are 210 x 10 = 2100 ways
Let the number of cards Aaron has : A
Given :
⊕ Bonny has twice as many cards as Aaron
⊕ Connor has 6 cards more than Bonny
⊕ Total cards : 101
⇒ Number of cards Bonny has : 2A
⇒ Number of cards Connor has : 2A + 6
⇒ Aaron cards + Bonny cards + Connor cards = 101
⇒ A + 2A + 2A + 6 = 101
⇒ 5A = 101 - 6
⇒ 5A = 95
⇒ A = 19
<u>Answer</u> : Aaron has 19 Cards
3/4
when it’s parallel it has the same slope!
