Answer:
The operation of 6*x only executes if x is greater or equal to 0, since x=-10 and -10 is less than 0, the operation does not execute. For this reason, the value of y using this code is None.
Explanation:
In python a function is defined with the syntaxis:
def function(x):
the operation to execute (x)
value to return
In this case, the function is foo and the parameter is x:
def foo(x):
if x>= 0:
return 6*x
The code starts by assigning a value to x. Then, the code asks if the value of x is grater or equal to 0, if this condition is meet, then the code returns the value of 6 times x, if not, then the code does not return a value. In this case, x is -10 and this value is not grater or equal to 0. Given that the condition is not met, then the code stops executing and the value of y is none.
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Answer:
There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:
Let a,b be two numbers.
c=a+b;
print(c);
But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:
Let a be the variable where the input numbers are stored.
while(f==1)
{
printf(“Enter number”);
scanf(“Take number into the variable a”);
sum=sum+a;
printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);
scanf(“Take the input into the variable f”);
}
print(Sum)
Explanation:
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Answer:
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