All categories

3 years ago

The sum of two numbers is 46 the difference is 16

2 answers:

8 0

Let the two numbers be represented by X and Y. Then we get the following SYSTEM of equations:
$x + y = 46 \\ x - y = 16$

We can subtract both formulas from each other to eliminate x.
$x - x + y - - y = 46 - 16$
$2y = 30$
Now, divide both sides by 2
$y = 15$

Given that X + Y = 46
$x + 15 = 46$
Subtract 15 from both sides
$x = 31$

Hence, X = 31 and Y = 15

Sindrei [870]3 years ago

3 0

31 and 15

31+15=46

31-15=16

You might be interested in

If f(x) varies directly with x and f(x) = 72 when x = 6, find the value of f(x) when x = 3.

Levart [38]

Answer:

Step-by-step explanation:

Since f(x) varies directly with x, f(x) can be expressed alternatively as \[f(x) = k * x\] where k is a constant value.

Given that f(x) is 72 when the value of x is 6.

This implies, \[72 = k * 6\]

Simplifying and rearranging the equation to find the value of k:

k = \frac{72}{6}

Hence k = 12

Or, \[f(x) = 12 * x\]

When x = 3, \[f(x) = 12 *3 \]

Or in other words, the value of f(x) when x=3 is 36

4 0

3 years ago

Read 2 more answers

5v+3=3-3v answer please

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

Subtracting 3 from both sides yields 5v = -3v, or 8v = 0. Then v must be 0.

7 0

3 years ago

two urns contain white balls and yellow balls the first urn contains 7 white balls and 7 yellow balls and the second urn contain

faltersainse [42]

Answer:

The correct answer option is b) $\frac{1}{6}$ .

Step-by-step explanation:

We are given that the first urn contains 7 white balls and 7 yellow balls and the second urn contains 3 white balls and 6 yellow balls. We are to find the probability that both balls drawn are white.

This means that the first must be white and the second ball must also be white.

P (w, w) = $\frac{7}{14}$ × $\frac{3}{9}$ = $\frac{1}{6}$

Therefore, the probability that both the balls drawn are white is 1/6.

5 0

4 years ago

2 1⁄7 × 3 3⁄4 × 5 1⁄3 = plz help me :,(

chubhunter [2.5K]

Answer:

42 6/7

Step-by-step explanation:

For me what i usually do is i convert the mixed number into a fraction, which for example:

Example and Explanation: Step 1

so since the number 7 is the denominator and the 2 is the mixed number, we can multiply these numbers, 2 x 7 = 14, then we add our numerator which in this case, is one, 14 + 1 = 15, and since the denominator stays the same, our fraction now is 15/7. We do the same for the others:

3 3/4:

3 x 4 = 12 + 3 = 15 = 15/4

5 1/3:

5 x 3 = 15 + 1 = 16 = 16/3

Now that they are all fractions we can finally do the multiplication

Multiplying Fractions: Step 2

Multiplying fractions does not require that the fractions have the same denominator. Instead, the numerators are multiplied with each other and the denominators are multiplied with each other. However, the resulting fraction may not be in lowest terms so it may need to be reduced. So since this is a three step multiplication problem, we will multiply two fractions first.

In this case I chose 15/7 x 15/4. so we just multiply from there, 15 x 15 = 225, and 7 x 4 = 28. So our fraction is 225/28, now we will multiply the other fraction: 225/28 x 16/3 which comes out to 3,600/84. Wow, thats a big number, now its time to..

Reduce: Step 3

This fraction is far too big to be a proper answer, so we will reduce, also known as simplifying.

Find the Greatest Common Factor (GCF) of 3600 and 84, if it exists, and reduce our fraction by dividing both numerator and denominator by it. GCF = 12,

=3600÷1284÷12=3007

Converting to a mixed number using long division with remainders for 300 ÷ 7.

300÷7=42r6

Therefore:

300/7 = 42 6/7

I am so sorry if i am wrong

3 0

3 years ago

In a certain survey, 513 people chose to respond to this question: "Should passwords be replaced with biometric security (fin

LenaWriter [7]

Answer:

The sample observations are not a randomsample, so a test about a population proportion using the normal approximating method cannot be used.

Step-by-step explanation:

The necessary conditions are

The sample must be random and independently selected from the normally distributed population.

n*p and n*q both must be greater than 5

There must be two outcomes "success" and "failure"

The number of trials must be fixed.

From the given information 2), 3)and 4) conditions are satisfied, but not 1) because we are not given that people are selected randomly.

Answer: The sample observations are not a randomsample, so a test about a population proportion using the normal approximating method cannot be used.

3 0

3 years ago