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velikii [3]
3 years ago
6

Evaluate for x = 2. A. 4 B. 5 C. 6 D. 7

Mathematics
1 answer:
kakasveta [241]3 years ago
7 0
I hope that A. Is the answer
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Which graph shows the solution to this system of inequalities<br> y2-3x+1<br> yo 21-3
Juli2301 [7.4K]

Answer:

18

Step-by-step explanation:

4 0
2 years ago
If the basic measuring unit in base-7 is 49 circles, what does the measuring unit of size .001seven look like
Serjik [45]

The measuring unit is the standard unit of a quantity

The measuring unit of size 0.001 is represented by one millionth circle

<h3>How to determine the unit of base 0.001</h3>

The basic measuring unit in base 7 is given as:

49 circles

The above can be represented as:

Base 7 = 49 circles

Represent the base with n.

So, we have the following rule

Circle = n^2

For measuring unit 0.001, we have:

Circle = 0.001^2

Evaluate the square

Circle = 0.000001

This means that,

The measuring unit of size 0.001 is represented by one millionth circle

Read more about measuring units at:

brainly.com/question/16393390

8 0
3 years ago
HEEEEEEEEELLLLLLLLLLLLPPPPPPPPPPP ASAP
VLD [36.1K]

Answer:

I'm not sure how to help-

Step-by-step explanation:

What would you need help with? C:

3 0
3 years ago
Pls answer I need help much confusion​
diamong [38]

Answer:

a. 1/6

Step-by-step explanation:find common denominator x/6

to get a denominator of 6 from 1/2, it turns into 3/6

denominator of 6 from 2/3, 4/6

4/6 is 1/6 greater than 3/6

5 0
3 years ago
When looking at the rational function f of x equals the quantity x minus one times the quantity x plus two times the quantity x
Luba_88 [7]

As per the given question, the expression of the function f(x) is as:

f(x)=\frac{(x-1)(x+2)(x+4)}{(x+1)(x-2)(x-4)}

Now, as per the definition of zeros, the zero is that value of x which when plugged into the function should make the function zero (it is also called "making the function vanish"). <u>In our case, plugging in "zero values" of x should make the numerator zero without making the denominator zero.</u> Now, if we plug in the given values of x, which are x=-1, x=2 and x=4 in the function we see that the <u>numerator does not become a zero but the denominator does</u>.

Thus, x=-1, x=2 and x=4 are not the zeros of the function and therefore, Sue is wrong. However, we do have discontinuities at the aforementioned values of x because the denominator becomes a zero at those points and as per the definition of a discontinuity the denominator should be a zero at that point. Therefore, Ed is correct.

8 0
4 years ago
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