Which graph best represents a continuous function with domain -3

What kind of sequence is the pattern 1, 6, 7, 13, 20, ...?

AlexFokin [52]

Answer:

The given sequence 6, 7, 13, 20, ... is a recursive sequence

Step-by-step explanation:

As the given sequence is

$6, 7, 13, 20, ...$

It cannot be an arithmetic sequence as the common difference between two consecutive terms in not constant.

As

$d = 7-6=1$ , $d = 13-7=6$

As d is not same. Hence, it cannot be an arithmetic sequence.

It also cannot be a geometrical sequence and exponential sequence.

It cannot be geometric sequence as the common ratio between two consecutive terms in not constant.

As

$r = 7-6=1$ , $r = 13-7=6$

$r = \frac{7}{6}$ , $r = \frac{13}{7}$

As r is not same, Hence, it cannot be a geometric sequence or exponential sequence. As exponential sequence and geometric sequence are basically the same thing.

So, if we carefully observe, we can determine that:

The given sequence 6, 7, 13, 20, ... is a recursive sequence.

Please have a close look that each term is being created by adding the preceding two terms.

For example, the sequence is generated by starting from 1.

${\displaystyle F_{1}=1$

and

$F_{n}=F_{n-1}+F_{n-2}$

for n > 1.

Keywords: sequence, arithmetic sequence, geometric sequence, exponential sequence

Learn more about sequence from brainly.com/question/10986621

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6 0

3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago

Identify the property or rule 85+0=

frez [133]

IdentityProperty of Addition OR Zero Property

8 0

3 years ago

Read 2 more answers

Kyle mows4 lawns a day 4 day a week 4 week a month and 4 months a year he makes $25 per lawn how much money did he make last yea

denis-greek [22]

Lets break this down step by step.

4+4+4+4=16 lawns a week.

16+16+16+16=64 lawns a month.

64+64+64+64=256 lawns a year.

Then we take 256 x $25 to get $6,400 last year.

6,400<---Answer

-Seth

8 0

3 years ago

Geometry Help please?

wariber [46]

Answers:
The coordinates of X are (-24,0)
The scale factor is 8/3.

------------------------------------------------------

To find the scale factor, you divide the y coordinates of the points Y and V
-8/(-3) = 8/3

Notice how multiplying the y coordinate of point V gets us to the y coordinate of point Y
-3*(8/3) = -24/3 = -8

Do the same for the x coordinate of point U
-9*(8/3) = -72/3 = -24
which is the x coordinate of point X

3 0

3 years ago