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geniusboy [140]
3 years ago
6

Bryan needs to build a fence around his rectangular vegetable garden. The length will be 2 feet longer than the width. If he use

s 16 feet of fencing; what will be the length and width? Brian plans on building a larger Garden next year. He would like to keep the length the same button extend the width of the garden so that it is square. is Brian extends the with to make a square, how much fencing will he need to surround the garden.
Mathematics
1 answer:
GalinKa [24]3 years ago
5 0
In order to do this, one side of the rectangle will be x+2, and the other will just be x. The x would be representing the width since the length is the width (x) plus two feet (+2). Next, you have to make an equation. So, since it all has to use 16 feet of fencing, you would set the two sides to be added to equal 16. So, it would be: 16=x+2+x. Then, you reduce that, so it would be: 16=2x+2. After that you just solve for x (which means that you want x by itself on one side of the = ). So, you would subtract 2 from both sides. Since 2-2=0, that would make the "+2" go away; since 16-2=14, that would replace the 16. So, your new equation is: 14=2x. After that you just divide both sides by 2 because 2 divided by 2=0. 14/2=7. So, you would end up getting: 7=x as your final answer.

Now, you just put 7 where x was in the sides. So 2x (which was the length) trims into: 2 times 7, which =14 and the x (which was the width) we already figured out was 7. This, the width would be 7, while the length would be 14.
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Step-by-step explanation:

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Un pájaro vuela en línea recta desde la Copa de un árbol a la de otro árbol que está 2 metros más abajo, formando un ángulo de v
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Step-by-step explanation:

Given,

Sin70° = 0.94

Cos70° = 0.34

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Refer the diagram attached for better understanding.

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4 years ago
Chad complained to his friend that he had five equations to solve for homework. Are all of the homework problems equations? Just
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What is the explicit rule for this geometric sequence? 4,45,425,4125,…
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You did not write the question correctly but I will try to answer the question according to 2 possible interpretations of your question.

Case 1:

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4,\  \frac{4}{5} ,\  \frac{4}{25} ,\  \frac{4}{125} ,\ .\ .\ .

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The explicit rule of a geometric sequence is given by T_n=ar^{n-1}

Therefore, the explicit rule of the given sequence is T_n=4\left( \frac{1}{5} \right)^{n-1}\ or\ 20\left( \frac{1}{5} \right)^n


Case 2:

Given the geometric sequence:

4,\ 4\cdot5,\ 4\cdot25,\ 4\cdot125,\ .\ .\ .

Common ratio is given by r= \frac{2nd\ term}{1st\ term} = \frac{4\cdot5}{4} = 5

The explicit rule of a geometric sequence is given by T_n=ar^{n-1}

Therefore, the explicit rule of the given sequence is T_n=4(5)^{n-1}\ or\ \frac{4}{5}(5)^n
4 0
3 years ago
Read 2 more answers
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