Do you know what you need to do to solve this problem?
Answer:
(-1, -1) Let me know if the explanation didn't make sense.
Step-by-step explanation:
If we graph the three points we can see what looks like a quadrilateral's upper right portion, so we need a point in the lower left. This means M is only connected to N here and P is only connected to N. So we want to find the slope of these two lines.
MN is easy since their y values are the same, the slope is 0.
NP we just use the slope formula so (y2-y1)/(x2-x1) = (-1-3)/(5-4) = -4.
So now we want a line from point M with a slope of -4 to intersect with a line from point P with a slope of 0. To find these lines weuse point slope form for those two points. The formula for point slope form is y - y1 = m(x-x1)
y-3 = -4(x+2) -> y = -4x-5
y+1 = 0(x-5) -> y = -1
So now we want these two to intersect. We just set them equal to each other.
-1 = -4x -5 -> -1 = x
So this gives us our x value. Now we can plug that into either function to find the y value. This is super easy of we use y = -1 because all y values in this are -1, so the point Q is (-1, -1)
The answer to your question is algebraic expressions :)
3-2x<7
Subtract 3 from both sides.
-2x<4
Divide -2 from both sides. (switch the sign because you are dividing a negative number)
x>-2
Answer:
1. -3 = -8, 0 = 1, 2 = 7
Step-by-step explanation:
1. Plug in the x values for x in the equation and graph the coordinates (examples; (-3, -8))
2. do the same thing as #1
example; y = -(-3) - 2
3. Plug in 2 into the equation, giving you your y value, and plug the coordinates in
4. you can make up the x coordinates, I would do -1, 0, 1, and 2. and just plug those in for the x in the equation and graph.
5. Follow the same steps as the last problems but just connect the points
6. Same steps as the other problems, just pick some points and plug them into the equation.
I hope this helps
