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4 years ago

If points a,b,c,d and ,e are collinear and in that order. Find AC if AE = x+50 and CE=x+32

Mathematics

2 answers:

Alla [95]4 years ago

7 0

By the segment addition postulate,
AC + CE = AE so AC = AE - CE
AC = (x+50) - (x+32)
AC = x+50-x-32
AC = 18

aliina [53]4 years ago

7 0

<h2>Answer:</h2>

Hence, we get: AC= 18

<h2>Step-by-step explanation:</h2>

It is given that:

A,B,C,D and E are collinear and in that order.

Also, we are asked to find the length of the line segment AC.

given that the length of the line segment AE is:

AE=x+50

and the length of the line segment CE is given by:

CE=x+32

Now we know that:

the length of the line segment AC is length of line segment AE minus the length of the line segment CE.

i.e.

$AC=AE-CE\\\\AC=x+50-(x+32)$

on opening the parentheses term we have:

$AC=x+50-x-32\\\\AC=x-x+50-32\\\\AC=0+18\\\\AC=18$

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Read 2 more answers

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