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gtnhenbr [62]
3 years ago
15

Tracy used the expression (25.6) (16.2) + (25.6) (36.5) + (16.2) (37.8) to find the surface area, in square centimeters, of the

rectangular pyramid below.
A rectangular pyramid. The rectangular base has a length of 25.6 centimeters and width of 16.2 centimeters. 2 triangular sides have a base of 25.6 centimeters and height of 36.5 centimeters. 2 triangular sides have a base of 16.2 centimeters and height of 37.8 centimeters.

Which statement best describes her work?
Tracy’s answer will be incorrect because she forgot the factor One-half in the expression representing the area of the triangular faces.
Tracy’s answer will be incorrect because the pyramid has five faces and her expression finds the sum of only three products.
Tracy’s answer will be correct because she made use of the fact that 2 (one-half) = 1 in her expression.
Tracy’s answer will be correct because a rectangular pyramid has only three faces and the expression finds the sum of three products.
Mathematics
2 answers:
Anarel [89]3 years ago
8 0

Answer:

Tracy’s answer will be correct because she made use of the fact that 2 (one-half) = 1 in her expression.

C

Deffense [45]3 years ago
3 0

So 25.6 + 16.2 + 25.6 + 36.5 + 16.2 + 37.8 = 1961.48

I would say the second statement would best describe her work, because it is giving the most detail out of those statements.

Hope this helps!

~Jarvis

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AVprozaik [17]

Answer:

\large\boxed{x=\dfrac{-3+\sqrt{40+10\sqrt{10}}}{2}}

Step-by-step explanation:

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x^2+3x=10^{1\frac{1}{2}}\\\\x^2+3x=10^{1+\frac{1}{2}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\x^2+3x=10\cdot10^\frac{1}{2}\qquad\text{use}\ \sqrt[n]{a}=a^\frac{1}{n}\\\\x^2+3x=10\sqrt{10}\qquad\text{subtract}\ 10\sqrt{10}\ \text{from both sides}\\\\x^2+3x-10\sqrt{10}=0\\\\\text{Use the quadratic formula}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\a=1,\ b=3,\ c=-10\sqrt{10}\\\\b^2-4ac=3^2-4(1)(-10\sqrt{10})=9+40\sqrt{10}\\\\x=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2(1)}=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2}\\\\x=\dfrac{-3-\sqrt{10+10\sqrt{10}}}{2}\notin D

6 0
3 years ago
Isosceles trapezoid ABCD has legs AB and CD, and base BC. If AB = 3y - 4, BC = 2y -3, and CD = 4y - 18, find the value of y.
Kryger [21]

Answer:

   (6)

Step-by-step explanation:

Since it is an isosceles trapezoid the length of the two legs (i.e.  AB = 5y-10 and CD = 2y+8) are equal.  In other words,

5y - 10 = 2 y + 8

Subtract 2y from each side:

5y - 2y - 10 = 8

Now add 10 to each side

5y - 2y - 10 + 10 = 8 + 10 =>

3y + 0 = 18 =>  

3y = 18 =>

y = 6

8 0
3 years ago
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liq [111]

Answer:

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Step-by-step explanation:

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Arlecino [84]
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olganol [36]

Answer:

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Step-by-step explanation:

-6 is more than -8.

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