Answer:
Yes
Step-by-step explanation:
Answer:
As you can see Rectangle L M NO and Rectangle L'M'N'O' are such that
1. Size of Rectangle L M NO > Size of Rectangle L'M'N'O'
2. Sides of, means length and breadth of Rectangle L M N O is not in proportion to Rectangle L'M'N'O'. i.e
3. Out of four possibilities given :
, Reflection and Rotation is not possible because in all the three cases Pre-image and image are not congruent or similar.
As in,Rectangle LMNO →when length and breadth get reduced by scale of 2 and 0 and Dilation by scale factor of< 1 we get Rectangle L'M'N'O'.Centre of dilation may be other than origin.
So, Stretching of preimage i.e Rectangle L M NO→ means Shrinking has taken place to get image Rectangle L'M'N'O'.As shrinking is not an option.
So, Dilation by a factor less than 1, center of dilation other than origin has taken place.
<h3>
Answer: -3</h3>
Work Shown:
g(x) = -x+2
g(5) = -5+2 ... replace every x with 5
g(5) = -3
Answer:
7/4 OR 1 3/4
Step-by-step explanation:
49/10 divided by 14/5
49/10 multiplied by 5/14
49x5 / 10x14
245/140
simplified or cancelled out to
7/4 OR 1 3/4
Solution : Given points to be fill are : 5 external points + 5 internal points
Total positions to be fill are 5+5 = 10
given number of sea shell to be placed are = 10
Here all sea shell are different so each sea shell is different from any other sea shell
if we interchange the position of any two sea shell we would be getting totally different
arrangement .
We can think this problem like 10 sea shell are to be placed at 10 different places
We start with placing first sea shell .
In the beginning we have 10 positions
once it is placed we pick second sea shell and now we have only 9 vacant places
once it is placed we pick next ses shell and we have 8 vacant places for it
we continue with it till we place the last sea shell for which we would be having
only 1 vacant place.
This way the total number of arrangements we get : 10x9x8x7x6x5x4x3x2x1 = 3628800
ANSWER = 3628800
