Question

Find the zeros (x-intercepts) of the quadractic function y=2/3(3x-2)(3x+6)

Answer 1

Answer:

x = - 2, x = $\frac{2}{3}$

Step-by-step explanation:

T o find the zeros let y = 0, that is

$\frac{2}{3}$ (3x - 2)(3x + 6) = 0 ← in standard form

Equate each factor to zero and solve for x

3x - 2 = 0 ⇒ 3x = 2 ⇒ x = $\frac{2}{3}$

3x + 6 = 0 ⇒ 3x = - 6 ⇒ x = - 2