Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Hello!
To solve this you have to find the ratio between the two cylinders
Cylinder 1 height is 30
Cylinder 2 height is 20
this is a 30:20 ratio
This can be reduced to a 3:2 ratio
Now you look for one that are also equal to 3:2
3 * 7 = 21
2 * 7 = 14
The answers are 3:2 and 21:14
Hope this helps!
Answer:
i think it has 4
Step-by-step explanation:
t + 15 is something on money
Answer:
x = 6/11
Step-by-step explanation:
−23(3x−4)+3x=56
Distribute
-69x + 92 +3x = 56
Combine like terms
-66x+92 = 56
Subtract 92 from each side
-66x+92-92 = 56-92
-66x =-36
Divide each side by -66
-66x/-66 = -36/-66
x = 6/11
The coordinated of the preimage would be :
x = x cos θ + y sin θ
y = x sin θ + y cos θ
where
x = -4
y = 7
θ = -90
hope this helps