Write the equation of line in slope-intercept form. Line parallel to y=0.5x+3 that passes through the point (−9,12)
2 answers:
A line parallel to the given one will have the same slope, 0.5. For the purpose here, it is convenient to start with a point-slope form of the equation, then simplify. For slope m and point (h, k), the equation of the line can be written as
... y = m(x -h) +k
We have m=0.5, (h, k) = (-9, 12), so the equation is ...
... y = 0.5(x +9) +12
... y = 0.5x +16.5
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Answer:
y = 4 sin( 0.5t - ) - 2
y = a sin ( 2t - ) + 2
Step-by-step explanation:
In the first question,
amplitude = 4
Period =
phase shift =
Vertical shift = -2
Angular velocity , w =
Here, w = = 0.5
The general equation of a wave is
y = a sin( wt + ∅ )
Putting above values in the equation,
y = 4 sin( 0.5t - ) - 2
In the second question,
Amplitude is not given so we will take it as a.
time period =
w = 2
Phase shift =
Vertical shift = 2
The equation is
y = a sin ( 2t - ) + 2