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Ainat [17]
4 years ago
13

John needs to paint a wall with spray paint. the wall has a diagonal of 43.6 feet and a height of 8.3 feet. if a spray can will

cover 21.5 square feet, how many cans will john need?
Mathematics
2 answers:
mixer [17]4 years ago
7 0
The wall is a rectangle, so by the pythagorean theorem, the diagonal squared minus the height squared equals the width squared. This gives a width of 42.80 feet. The area of the wall is width (42.80 ft) x height (8.3 ft), equal to 355.26 square ft. The can covers 21.5 square feet, so John needs 16.52 cans to cover the wall. As he can't buy half a can, John should purchase 17 cans of spraypaint.<span>The wall is a rectangle, so by the pythagorean theorem, the diagonal squared minus the height squared equals the width squared. This gives a width of 42.80 feet. The area of the wall is width (42.80 ft) x height (8.3 ft), equal to 355.26 square ft. The can covers 21.5 square feet, so John needs 16.52 cans to cover the wall. As he can't buy half a can, John should purchase 17 cans of spraypaint.</span>
marta [7]4 years ago
3 0
Diagonal of a wall: d=43.6ft
Height of a wall: h=8.3ft
Length of a wall: l
d²=h²+l², l²=d²-h², l=√(d²-h²)
l=√(43.6²-8.3²), l=42.8ft
Area of a wall is: l*h=8.3*42.8=355.24ft²
One spray can can cover 21.5ft². 355.24/21.5=16.52
John will need 17 cans of spray.
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