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joja [24]
4 years ago
15

HELP PLEASE..answer fast please and show all work and explain how to solve

Mathematics
1 answer:
zhenek [66]4 years ago
7 0
\cfrac{a}{sinA}=  \cfrac{b}{sinB} \ \  \to \\ sinB= \cfrac{b*sinA}{a} = \cfrac{10*sin15^o}{9}= 0.2875 \ \ \to \  m \angle B=16.7^o \\ \\ \\  m \angle C=180- m \angle A- m \angle B=180-15-16.7=148.3^o \\  \\  \\ \cfrac{a}{sinA}=  \cfrac{c}{sinC} \ \ \to \ c= \cfrac{a*sinC}{sinA}=  \cfrac{9*sin148.3^o}{sin15^o} \approx 18.3
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The slope of the parallel line is 3/4

<h3>How to determine the slope?</h3>

The equation is given as:

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Rewrite as:

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