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3 years ago

5

How do you round an irrational number to the nearest hundredth

1 answer:

MariettaO [177]3 years ago

7 0

To round to the nearest cent, nearest penny, or nearest hundredth, you will need to locate the hundredths place. Then look at the digit to the right. If it is 5 or above, the number in the hundredths place will be increased by 1 and all the rest of the numbers after it are dropped. If the number is 4 or below, you leave the digit in the hundredths place alone and drop all the rest of the numbers after.

<span>Just remember, if the problem asks you to round to the nearest hundredth, make the end result look like money, meaning only two digits after the decimal point!</span>

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The following conditional statement true. what is the statements converse and is the converse true?

Lera25 [3.4K]

A converse is when we switch the hypothesis and conclusion, so "if a figure is a square then it has four right angles" the converse would be "If a figure has four right angles then it is a square" Which is false because of rectangles, your answer is D.

4 0

3 years ago

Natasha_Volkova [10]

Answer:

x = 2, y = -1.

Step-by-step explanation:

2x + y = 3

x - y = 3

Adding the 2 equations eliminates y:

3x = 6

x = 2.

Substitute for x in the first equation:

2(2) + y = 3

y = 3 - 4

y = -1.

Check the results by substitution in equation 2:

2 - (-1)

= 2 + 1 = 3 .

Checks OK.

6 0

2 years ago

Read 2 more answers

Evaluate 9 ÷ 3[(18 − 10) − 22].

dlinn [17]

Answer:

-42

Step-by-step explanation:

3 0

3 years ago

Can i please get help with this question?

Aleonysh [2.5K]

1,5 . n = 13,65

We know:

$1,5=\frac{15}{10}$

and

$13,65=\frac{1365}{100}$

So,

$\frac{15}{10}.n=\frac{1365}{100}$

Pass $\frac{15}{10}$ as division.

$n = \frac{\frac{1365}{100}}{\frac{15}{10}}$

Btw, we also know:

$\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a.d}{b.c}$

So,

$n = \frac{\frac{1365}{100}}{\frac{15}{10}}$

$n = \frac{1365.10}{100.15}$

$n = \frac{13650}{1500}$

$n = \frac{91}{10}$

$n = 9,1$

5 0

3 years ago

The average weight of 3 containers A,B and C is 3.2kg. Container A is twice as heavy as container B. Containers B is 400 g heavi

dlinn [17]

Answer:

The weight of container C is 2.1kg.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the weight of container A.

y is the weight of container B.

z is the weight of container C.

The average weight of 3 containers A,B and C is 3.2kg.

This means that the total weight is 3*3.2 = 9.6kg. So

$x + y + z = 9.6$

Container A is twice as heavy as container B.

This means that $x = 2y$ .

Containers B is 400 g heavier than container C.

400g is 0.4kg. So

This means that $y = z + 0.4$ , or $z = y - 0.4$

Replacing y and z as functions of x in the first equation:

$x + y + z = 9.6$

$2y + y + y - 0.4 = 9.6$

$4y = 10$

$y = \frac{10}{4} = 2.5$

Container C

$z = y - 0.4 = 2.5 - 0.4 = 2.1$

The weight of container C is 2.1kg.

4 0

3 years ago