150% of 84 i believe lol .
Answer:
20 units²
Step-by-step explanation:
The x-intercepts are symmetrically located around the x-coordinate of the vertex, so are at
1.5 ± 5/2 = {-1, 4}
Using one of these we can find the unknown parameter "a" in the parabola's equation (in vertex form) ...
0 = a(4 -1.5)² +12.5
0 = 6.25a +12.5 . . . . . simplify
0 = a +2 . . . . . . . . . . . divide by 6.25
-2 = a
Then the standard-form equation of the parabola is ...
y = -2(x -1.5)² +12.5 = -2(x² -3x +2.25) +12.5
y = -2x² +6x +8
This tells us the y-intercept is 8. Then the relevant triangle has a base of 5 units and a height of 8. Its area is given by the formula ...
A = (1/2)bh = (1/2)(5)(8) = 20 . . . . units²
Answer:
f(2) = 16
or
y = 16
Step-by-step explanation:
Step 1: Write out function
y = 6x + 4
Step 2: Define variable for problem
<em>x</em> = 2
Step 3: Plug into function f(x)
f(2) = 6(2) + 4
f(2) = 12 + 4
f(2) = 16
Step 4: Change f(2) to y
y = 16
Answer:
300
——
11
Step-by-step solution
200/2*3/11
100*3/11
300/11
300/11 or 27 3/11 or 27.27
The initial velocity is -150m/s.
Remember that:
V(t) = Vi + at, where v(t) is velocity at time t, Vi is initial velocity, and a is acceleration.
We know that the vehicle stopped after 30 seconds, so V(30) = 0.
Let's plug the useful info into our function and solve for a:
0 = -150 + a*30 Add 150 to both sides
150 = 30a Divide both sides by 30
a = 5 m/s²
The average acceleration is 5 meters per second squared.