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Klio2033 [76]
3 years ago
9

The function C(x) = x 2 + 78 x + 29 models the cost, in hundreds of dollars, to produce x thousand pens. Find and interpret C(0)

, C(2) and C(4)
Mathematics
1 answer:
VashaNatasha [74]3 years ago
6 0

Answer:

Step-by-step explanation:

Given the function C(x) = x 2 + 78 x + 29 models the cost, in hundreds of dollars, to produce x thousand pens, we are to interpret C(0), C(2) and C(4).

For C(0), we are to substitute x = 0 into the given function;

C(0) = 0²+78(0)+29

C(0) = 0+0+29

C(0) = 29

Since the cost C(x) is in hundreds of dollars, C(0) = 2900

<em>C(0) means that the cost of producing 0 thousand pen is $2,900</em>

For C(2), we are to substitute x = 2 into the given function;

C(2) = 2²+78(2)+29

C(2) = 4+156+29

C(2) = 189

Since the cost C(x) is in hundreds of dollars, C(2) = 189*100 = $18900

<em>C(2) means that the cost of producing 2 thousand pens is $18,900</em>

For C(4), we are to substitute x = 4 into the given function;

C(4) = 4²+78(4)+29

C(4) = 16+312+29

C(4) = 357

Since the cost C(4) is in hundreds of dollars, C(4) = 357

<em>C(4) means that the cost of producing 4 thousand pens is $35,700</em>

<em></em>

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Find 3 consecutive integers such that twice the first, plus three times the second, plus four times the third is 20. Please show
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Since the integers are consecutive, you could call them 'x', x+1,and x+2.
Or you could all them  x-1, 'x', and x+1.
Or you could call them  x-2, x-1, and 'x'.
It's up to you.  Each of those sets describes 3 consecutive numbers.

Most people will call them 'x', x+1, and x+2, so let's do that.

Now just go through the question and make the quantities it talks about:

"twice the first" . . . . 2(x)
"three times the second" . . . . 3(x+1)
"four times the third" . . . . . 4(x+2)

and finally, it says that the sum of those things is 20.
This should not be a major problem.

2x + 3(x+1) + 4(x+2) = 20

You can probably handle it from here, but I'll continue anyway.
The next thing to do is take out all the parentheses:
3(x+1) = 3x + 3
4(x+2) = 4x + 8
Now add up the whole thing again, but without parentheses:

2x + 3x + 3 + 4x + 8 = 20

Gather all the x's together, and all the naked numbers together:

(2x + 3x + 4x) + (3 + 8) = 20

Addum up:   9x + 11 = 20

Subtract 11 from each side:   9x = 9

Divide each side by  9 :     x = 1

The first integer = x . . . . . . . <em>1</em>
The second integer = x+1 . .<em> . 2</em>
The third integer = x+2 . . . . .<em> 3 </em>

<u>Check:</u>

"twice the first" . . . . . . . . . . 2(1) = 2
"three times the second". . . 3(2) = 6
"four times the third" . . . . . . 4(3) = 12

Addum up:  2 + 6 + 12 = 20 just like the question said.      yay!



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