Select the values for p, q, and r that will make the following equation true.

Mathematics

1 answer:

gregori [183]4 years ago

5 0

Answer:

P= 3

Q= -14

R= -5

Step-by-step explanation:

Just solve the equation on the right side, you'll get:

=3x^2 -15x +x -5

=3x^2 -14x -5

Now compare it to the equation on the left side,

The coefficient of x^2 on the left is "p", on the right that we just solved is 3.

Same for "q" which is the coefficient on the left, on the right it's -14.

And for "r" it's -5 from the equation on the right.

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How many intergers between 1 and 500 inclusive are divisible by both 6 and 9 but not 4

creativ13 [48]

I think the answer is 14.
the smallest common multiple of 6 and 9 is 18. all multiples of 18 is divisible by 6 and 9.
500 ÷18=27.777777777
there are 27 numbers between 1 and 500 that are divisible by both 6 and 9, but when the quotient is an even number, the multiple of 18 is divisible by 4 as well, so only the multiples of 18 that produce an odd quotient satisfy the requirement.
from 1 to 27, there are 14 odd numbers.

7 0

3 years ago

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Sav [38]

Answer:

k = 4

Step-by-step explanation:

Rearrange so that like terms are on either side of the equation

4k - 2k - 2k + 2k = 5 + 3

Simplify

2k = 8

Divide both sides by two to make k on its own