Yes.
First, you find the fractions with common denominators: 9/10 is equal to 72/80 and 6/8 is equal to 60/80.
Since 72 is greater than 60, 9/10 is greater than 6/8.
The domain is all real numbers except -6 and 0. Hence, domain D: {x ∈ ℝ| x ≠ –6, 0}
Hence the range is all real numbers except -3 and 3. Hence, range R: (–∞, –3) ∪ (3, ∞)
Given the following functions:

First we need to get the composite function f(g(x))

Get the domain
The domain the values of x for which the function exists. The function cannot exists at when x = -6 and x = 0
- Hence the domain is all real numbers except -6 and 0. Hence, domain D: {x ∈ ℝ| x ≠ –6, 0}
The range is the value of y for which the function exists. The function cannot exists at when x = -6 and x = 0
- Hence the range is all real numbers except -3 and 3. Hence, range R: (–∞, –3) ∪ (3, ∞)
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Answer:
Step-by-step explanation:
Your maths problem
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5
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3
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2
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1
Answer:
8x10-3 is greater than 4x10-6 by 43 2x10-3 17 2x10-9=11 2x10=202x10=20=68
Step-by-step explanation:
Answer:
B+54
Step-by-step explanation:
If Jackie has B beads, and Sally has 54 more than that, then you are adding 54 to B