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3 years ago

9

Any help please? :( i really need it

2 answers:

Alika [10]3 years ago

6 0

The answer is F(22.5)

Aloiza [94]3 years ago

4 0

Yes! All you have to do is set up some ratios. Since the triangles are similar,

If you put 15 over 12 (15/12) then you would put x over 18 (x/18)

Then cross multiply!
(Shown above)

Your answer is x = 22.5

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Which values of m and b will create a system of equations with no solution? Select two options.

emmasim [6.3K]

Answer:

Step-by-step explanation:

y = -2x + 2/2.....slope = -2, y int = 2/2(or just 1)

y = -2x + 3/2....slope = -2, y int = 3/2

when the equations have the exact same slope, but different y intercepts.....and this one does....then there is no solution because these are parallel lines....they never cross each others path.

6 0

3 years ago

Rita ha decidido emprender un negocio de ventas de productos de protección personal, para lo cual tiene que inventir 1/3 de su d

d1i1m1o1n [39]

Answer:

3/10

Step-by-step explanation:

Subtract the sum of 1/3, 4/15 and 1/10 from 1:

10/30 + 8/30 + 3/30 = 21/30, or 7/10

Then: 1 - 7/10 = 3/10

6 0

3 years ago

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

To get a free bonus gift, you must spend at least $100 in a

mart [117]

Spent amount= $81.50

Pending= $18.50

7 0

3 years ago

The equation y = 6.85x could represent a variety of different situations .

Marina86 [1]

Answer:

For every x feet of rope purchased, the total cost(y) increases by $6.85.

Step-by-step explanation:

4 0

3 years ago