I hope this helps you
[20x^2/4x^2y]+[4xy^2/4x^2y]-[8y^2/4x^2y]
[5/y]+[y]-[4y/x^2]
Answer= -54
-2(bx-5)=16
If b is 3, then it changes to -2(3x-5)=16
We want to find x, right? Then we must do -2•3x and -2(-5). The result would be -6x and 10.
Then again, the equation would change -6x+10=16
Which would be -6x=6
Is x=6/6
And then x would be 1
Please tell me what I did wrong and if it is wrong, comment on this and I’ll fix my mistake!^^
Step-by-step explanation:
See attached picture.
First, compare the highest term of the dividend (x²) to the highest term of the divisor (x). We need to multiply the divisor by x.
When we do that, we get x² + 5x. Subtracting this from the dividend, we get -9x + 11.
Now repeat the process. Compare the highest term of the new dividend (-9x) to the highest term of the divisor (x). We need to multiply by -9.
When we do that, we get -9x − 45. When we subtract from the new dividend, we get 56.
So the quotient is x − 9, and the remainder is 56.
Answer:
y = x - 11
Step-by-step explanation:
First, turn the f(x) into a y:
y = x + 2 + 9
Now, switch the x and y.
x = y + 2 + 9
Add like terms.
2 + 9 = 11
x = y + 11
Now, solve for y. Subtract 11 on both sides.
y = x - 11
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