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4 years ago

-2 1/4 x 3 1/3 in lowest term fraction

Mathematics

2 answers:

blondinia [14]4 years ago

7 0

=-21/4*31/3
=-9/4*10/3
=-90/12
=-71/2

Korvikt [17]4 years ago

5 0

- 2 1/4 * 3 1/3
= -9/4 * 10/3
= -90/12
= = -7 1/2 answer

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Meg walks to school and work each day and wants to track how far she walks each day. In the morning, Meg walks 7 blocks due east

worty [1.4K]

Answer:

I am pretty sure it is 19 blocks because it is 14 blocks before going back home. She needs to walk 3 blocks west and 2 blocks south. 14+3+2=19

Step-by-step explanation:

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3 years ago

To mail a letter to Vienna, Austria the post office charges a flat rate of $9.75 and an additional $0.50 for every ounce the let

bearhunter [10]

Missing details

Which type of function model would be appropriate for this situation?

Answer:

Linear function

Step-by-step explanation:

Given

$y = 0.50x +9.75$

Required

The function model

A function of the form:

$y = mx + b$

is referred to as a linear function where

$m = slope/rate$

$b=y\ intercept$

By comparison:

$m = 0.50\ b = 9.75$

<em>So, it is a linear function (linear model)</em>

4 0

3 years ago

Prove that:

Lorico [155]

A.)

$\csc^2(x) \tan^2 (x)- 1 = \tan^2(x)$

Use the identities $\csc x = 1 / \sin x$ and $\tan x = \sin x / \cos x$ on the left-hand side

$\begin{aligned}
\text{LHS} &= \csc^2(x) \tan^2 (x)- 1 \\
&= \frac{1}{\sin^2 (x)} \cdot \frac{\sin^2 (x)}{\cos^2 (x)} - 1 \\
&= \frac{1}{\cos^2 (x)} - 1
\end{aligned}$

Make 1 have a common denominator to allow for fraction subtraction
Multiply the numerator and denominator of 1 by cos^2 x

$\begin{aligned} \text{LHS} &= \frac{1}{\cos^2 (x)} - 1 \cdot \tfrac{\cos^2 (x)}{\cos^2 (x)} \\
&= \frac{1}{\cos^2 (x)} - \frac{\cos^2 (x)}{\cos^2 (x)} \\
&= \frac{1 - \cos^2 x}{\cos^2 (x)}
\end{aligned}$

Use Pythagorean identity for the numerator.

If $\sin^2 (x) + \cos^2(x) = 1$ then subtracting both sides by $\cos^2 (x)$ yields $\sin^2(x) = 1 - \cos^2(x)$ . We can substitute that into the numerator

$\begin{aligned} \text{LHS} &= \frac{1 - \cos^2 (x)}{\cos^2 (x)} \\
&= \frac{\sin^2 (x)}{\cos^2 (x)} \\
&= \tan^2 (x) && \text{Since } \tan x = \tfrac{\sin x }{\cos x} \\
&= \text{RHS}
\end{aligned}$

======

b.)

$\dfrac{\sec(x)}{\cos(x)} - \dfrac{\tan(x)}{\cot(x)} = 1$

For the left-hand side:
By definition, $\sec(x) = 1/\cos(x)$ and $\tan (x) = 1/\cot (x)$

$\begin{aligned}
\text{LHS} &= \dfrac{\sec(x)}{\cos(x)} - \dfrac{\tan(x)}{\cot(x)} \\
&= \dfrac{ \frac{1}{\cos(x)} }{\cos(x)} - \dfrac{\frac{1}{\cot(x)}}{\cot(x)} \\
&= \frac{1}{\cos^2 (x)} - \frac{1}{\cot^2(x)} 
\end{aligned}$

Since $\cot (x) = \cos (x) / \sin (x)$

$\begin{aligned} \text{LHS} &= \frac{1}{\cos^2 (x)} - \frac{1}{\frac{\cos^2(x)}{\sin^2(x)} } \\ &= \frac{1}{\cos^2 (x)} -\frac{\sin^2(x)}{\cos^2(x)} \\ &= \frac{1 - \sin^2(x)}{\cos^2 (x)} \end{aligned}$

Using Pythagorean identity, $\cos^2(x) = 1 - \sin^2(x)$ so

$\begin{aligned} \text{LHS} &= \frac{\cos^2(x)}{\cos^2 (x)} \\
&= 1 \\
&= \text{RHS}
\end{aligned}$

6 0

3 years ago

What is the solution to 6x+y=24

zimovet [89]

6x+y=24

-6x to both sides

y=-6x+24

divide by 6

y=-4

I am sorry if this is wrong.

5 0

3 years ago

Svetlana hair is 4 centimeters long. Her hair grows 1.5 cm per month. Svetlana wants her hair to grow so at least 7 cm long. Wri

Andrei [34K]

Let "per month" = m

The inequality is

1.5m + 4 ≥ 7

+ 4: Her hair right now is 4 cm long

1.5m: Her hair grows 1.5 per month (m)

≥ 7: She wants it to be at least 7 or more.

1.5m + 4 ≥ 7 is your answer

hope this helps

3 0

3 years ago