The <em>correct answer</em> is:
D) reflect over the y axis and then reflect again over the y axis.
Explanation:
Logically, if we reflect a figure across the y-axis and then reflect across the y-axis again, we have undone what we originally did, and the figure is back in its original position.
Algebraically, reflecting across the y-axis maps every point (x, y) to (-x, y). Reflecting this point across the y-axis maps (-x, y) to (x, y); this is our original point.
Draw a diagram to illustrate the problem as shown below.
The area of triangle acb is
A₁ = (1/2)*20*h = 10h
The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h
The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8
Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.
Answer:
Option C) The first equation is y= 2/3x-4 when written in slope-intercept form .
Step-by-step explanation:
We have

The first equation is in Standard form .
Convert to slope Intercept form .
Isolate the Variable y .

Divide by 3 both sides .


The second equation is in slope Intercept form .
Convert to standard form
Multiply by 5 both sides to remove the fraction .


<h3><u>Verify each statement :- </u></h3>
<h3>• case A) Both equations are in slope-intercept form.</h3>
- Because only the second equation is in slope -intercept form
<h3>• case B) Neither equation is in slope-intercept form .</h3>
- Because, the second equation is in slope -intercept form
<h3>• case C) The first equation is y= 2/3x-4 when written in slope-intercept form</h3>
<h3>• case D)The second equation is 3x+5y=10 when written in slope-intercept form.</h3>
- Because, the second equation is 3x+5y=10 when written in standard form .
<h2>I hope this helps you !! </h2>