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3 years ago

5

The price of a computer was decreased by 30% to £147. What was the price before the decrease?

1 answer:

zhuklara [117]3 years ago

7 0

A decrease by 30%, means that the price is now 70% of the original price ( 100% - 30% = 70%)

To find the original price divide the new price by the percent of the original price it is now.

147 / 0.70 = 210

The original price was £210

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2 years ago

Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex

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$z = -1.53$ --- test statistic

$p = 0.1260$ --- p value

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Step-by-step explanation:

Given

$n_1 = 80$ $\bar x_1= 104$ $\sigma_1 = 8.4$

$n_2 = 70$ $\bar x_2 = 106$ $\sigma_2 = 7.6$

$H_o: \mu_1 - \mu_2 = 0$ --- Null hypothesis

$H_a: \mu_1 - \mu_2 \ne 0$ ---- Alternate hypothesis

$\alpha = 0.05$

Solving (a): The test statistic

This is calculated as:

$z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}$

So, we have:

$z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}$

$z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}$

$z = \frac{-2}{\sqrt{0.8820 + 0.8251}}$

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$z = \frac{-2}{1.3066}$

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Solving (b): The p value

This is calculated as:

$p = 2 * P(Z < z)$

So, we have:

$p = 2 * P(Z < -1.53)$

Look up the z probability in the z score table. So, the expression becomes

$p = 2 * 0.0630$

$p = 0.1260$

Solving (c): With $\alpha = 0.05$ , what is the conclusion based on the p value

We have:

$\alpha = 0.05$

In (b), we have:

$p = 0.1260$

By comparison:

$p > \alpha$

i.e.

$0.1260 > 0.05$

So, we fail to reject the null hypothesis.

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2 years ago

-52 times the difference a number and 97 is equal to the number plus 39

VLD [36.1K]

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+52x +52x

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____ ____
53x 53x

94.43 = x

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2 years ago