Answer:
Step-by-step explanation:
Area of square= l×l
Area of square= 6mm × 6mn
Area if square = 36 mm²
Area of triangle 1= ½b ×h
Area of triangle 1= ½ (6mm)(8mm)
Area of triangle 1 = 24 mm²
Area of triangle 2 is the same as area of traingle 1 because they have the same base and hight
: . area of triangles is 48mm²
Area of the figure= Area of square + Area of triangles
A of figure = 36+48
A of figure = 84 mm²
Option 2
Use trapezium formula
Area of trapezium= (a+b)/2 * h
a=6 mm (base)
b=8+6=14 mm (Base)
h= 6mm (height)
Therefore the area of triangle= 24mm² as calculated in option 1
Area of the figure= Area of trapezium +Area of triangle
Area of figure = 60+24
= 84 mm²
Answer: d) -5, -40, -640
<u>Step-by-step explanation:</u>
Answer:
348 cents per pack
Step-by-step explanation:
$3.48 348 cents
----------- or ----------------- = 348 cents per pack
1 pack 1 pack
Answer:
W₂ is three times W₁ (W₂ = 3W₁)
Step-by-step explanation:
Applying,
W = ke²/2............. Equation 1
Where W = workdone in stretching the spring, k = spring constant, e = extension.
For W₁,
W₁ = ke₁²/2
Given: e₁ = 30-20 = 10 cm = 0.1 m
Substitute these value into equation 1
W₁ = k(0.1²)/2
W₁ = 0.005k Joules
For W₂,
W₂ = (ke/2)-W₁
Given: e = (40-20) = 20 cm = 0.1 m
Substitute these value into equation 1
W₂ = (k×0.2²/2)-0.005
W₂ = 0.015k Joules.
W₂/W₁ = 0.015k/0.005k
W₂/W₁ = 3
Therefore,
W₂ = 3W₁
Answer:
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Step-by-step explanation:
