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Sever21 [200]
4 years ago
7

1.What is the simplified form of each expression?

Mathematics
1 answer:
olga nikolaevna [1]4 years ago
6 0
<h2>Answer with explanation:</h2>

<u>Ques 1)</u>

A)

         We are given a expression as:

    7x^{-8}\times 6x^3

It could also be written as:

  (7\times 6)\times x^{-8}\times x^3\\\\\\=42\times x^{-8+3}\\\\\\=42x^{-5}\\\\\\=\dfrac{42}{x^5}

  Option: a is the answer.

B)

     (-2x^8)\times 3y^9\times 2x^4

which is solved as follows:

(-2\times 3\times 2)\times x^8\times y^9\times x^4\\\\\\=-12x^{8+4}\times y^9\\\\\\=-12x^{12}y^9

<u>Ques 2)</u>

A)

The expression is:

         (8\times 10^7)(7\times 10^4)

It is solved as:

  =(8\times 7)\times 10^7\times 10^4\\\\\\=56\times 10^{7+4}\\\\\\=56\times 10^{11}\\\\\\=5.6\times 10^{12}

                 Option: b is the answer.

B)

           (7\times 10^{-4})(9\times 10^{-10})

On simplifying:

     =7\times 9\times 10^{-4}\times 10^{-10}\\\\\\=63\times 10^{-4-10}\\\\\\=63\times 10^{-14}\\\\\\=6.3\times 10^{-14+1}\\\\\\=6.3\times 10^{-13}

                   Option: a is the answer.

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Last school year, the student body of a local university consisted of 30% freshmen, 24% sophomores, 26% juniors, and 20% seniors
tino4ka555 [31]

Answer:

\chi^2 = \frac{(83-90)^2}{90} +\frac{(68-72)^2}{72}+\frac{(85-78)^2}{78}+\frac{(64-60)^2}{60} = 1.66

And the answer would be:

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Step-by-step explanation:

We need to conduct a chi square test

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

the observed values for this case are:

Freshemen=83

Sophomores=68

Juniors = 85

Seniors= 64

The expected values for this case are:

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Sop_E =0.24*300= 72

Jun_E = 0.26*300 =78

Sen_E = 0.20*300= 60

Then the statistic would be given by:

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And the answer would be:

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4 0
4 years ago
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