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Sever21 [200]
4 years ago
7

1.What is the simplified form of each expression?

Mathematics
1 answer:
olga nikolaevna [1]4 years ago
6 0
<h2>Answer with explanation:</h2>

<u>Ques 1)</u>

A)

         We are given a expression as:

    7x^{-8}\times 6x^3

It could also be written as:

  (7\times 6)\times x^{-8}\times x^3\\\\\\=42\times x^{-8+3}\\\\\\=42x^{-5}\\\\\\=\dfrac{42}{x^5}

  Option: a is the answer.

B)

     (-2x^8)\times 3y^9\times 2x^4

which is solved as follows:

(-2\times 3\times 2)\times x^8\times y^9\times x^4\\\\\\=-12x^{8+4}\times y^9\\\\\\=-12x^{12}y^9

<u>Ques 2)</u>

A)

The expression is:

         (8\times 10^7)(7\times 10^4)

It is solved as:

  =(8\times 7)\times 10^7\times 10^4\\\\\\=56\times 10^{7+4}\\\\\\=56\times 10^{11}\\\\\\=5.6\times 10^{12}

                 Option: b is the answer.

B)

           (7\times 10^{-4})(9\times 10^{-10})

On simplifying:

     =7\times 9\times 10^{-4}\times 10^{-10}\\\\\\=63\times 10^{-4-10}\\\\\\=63\times 10^{-14}\\\\\\=6.3\times 10^{-14+1}\\\\\\=6.3\times 10^{-13}

                   Option: a is the answer.

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8. Let R be the relation on the set of all sets of real numbers such that SRT if and only if S and T have the same cardinality.
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Answer:

We must prove that the relation is reflexive, symmetric and transitive. Recall that to sets have the same cardinality if there exist a bijective mapping between them.

<em>Reflexive: </em>Take the identity map I:S\rightarrow S, which is bijective. Then SRS.

<em>Symmetric:</em> If SRT then, there exist a bijective map f:S\rightarrow R. In order to prove that TRS just take the inverse map of f: f^{-1} which is also bijective. Therefore, TRS.

<em>Transitivity: </em>Suppose that SRT and TRU. Also, assume that f is the bijective map between S and T, and g the bijective map between T and U. It is not difficult to check that the map h=g(f) is bijective and h:S\rightarrow U. Therefore, SRU.

Hence, the relation R is an equivalence relation.

The equivalence class of the set {0,1,2} is the class of all the sets with three elements, and we can associate it with the number 3. There is a construction of natural numbers based on this idea.

The equivalence class of Z is the same equivalence class of N. Therefore, is the class of all denumerable or countable sets.

Step-by-step explanation:

When we want to prove that a given relation R is equivalence, we need to check that R satisfies all the three conditions: reflexive, symmetric and transitivity. Usually the first two are very simple to prove and comes directly from the definition. The transitivity is more tricky. In this case we need to recall the definition of cardinality.

7 0
3 years ago
What is the additive inverse of the polynomial –9xy2 + 6x2y – 5x3?
masya89 [10]
Additive inverse of 9xy² + 6x²y - 5x³

-1(9xy² + 6x²y - 5x³) ⇒ (-1)(9xy²) + (-1)(6x²y) + (-1)(-5x³)

<span>-9xy² - 6x²y + 5x³ is the additive inverse of the given polynomial.</span>
5 0
3 years ago
Read 2 more answers
You can mow a lawn in 2 hours with a ride on mower and your friend can mow a lawn in 3 hours with a hand mower. How much time wi
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Answer:

Step-by-step explanation:

If you can mow a lawn in 2 hours, then you get 1/2 of the job done in 1 hour.

If your friend can mow the same lawn in 3 hours, then he can get 1/3 of the job done in 1 hour.

The equation for the time it would take for both of you to do the job together, then, is

\frac{1}{2} +\frac{1}{3} =\frac{1}{x}

where x is the number of hours it takes for both of you to do this job.  Get rid of the denominators to solve for x.  Do this by multiplying everything by the LCD, which is 6x.

6x(\frac{1}{2} +\frac{1}{3} =\frac{1}{x} ) which simplifies to

3x + 2x = 6 and

5x = 6

x = 6/5 or 1 1/5 hours

7 0
3 years ago
There are a total of 63 bikes If the ratio of blue bikes to Black bikes is 4 to 5 how many of the bikes are blue
hodyreva [135]

Answer:

28 blue bikes

Step-by-step explanation:

There follows a relatively simple method for solving this problem:

Let c be a counter.  Then 4c + 5c = 63, and 9c = 63.  Thus, c = 7.

Then the number of blue bikes is 4(7) = 28, and the number of black ones is 5(7) = 35.  Note that 28 + 35 comes to 63.

There are 28 blue bikes.

5 0
3 years ago
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