A randomized study compared two different systems for tracking baggage at an airport. The treatment group using System A reporte
d a mean of 18.5 lost bags per day. The treatment group using System B reported a mean of 16.6 lost bags per day.
To determine if the results are significant, the data are re-randomized and the differences of the means are shown in the dot plot.
What is the best conclusion to make based on the data?
a) The difference of the means is not significant because the re-randomizations show that it is outside the range of what could happen by chance.
b) The difference of the means is significant because the re-randomizations show that it is within the range of what could happen by chance.
c) The difference of the means is significant because the re-randomizations show that it is outside the range of what could happen by chance.
d) The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.
To determine if the results are significant, the data are re-randomized and the differences of the means are shown in the dot plot.
What is the best conclusion to make based on the data?
a) The difference of the means is not significant because the re-randomizations show that it is outside the range of what could happen by chance.
b) The difference of the means is significant because the re-randomizations show that it is within the range of what could happen by chance.
c) The difference of the means is significant because the re-randomizations show that it is outside the range of what could happen by chance.
d) The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.
2 answers:
You might be interested in
Answer:
0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
Find the probability that he weighs between 170 and 220 pounds.
This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.
X = 220
has a pvalue of 0.6554
X = 170
has a pvalue of 0.2743
0.6554 - 0.2743 = 0.3811
0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.