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Alisiya [41]
3 years ago
7

What type of confined space has the normal hazards presented by a confined space plus additional hazards?

Biology
1 answer:
PIT_PIT [208]3 years ago
7 0
Hello,

The answer is option A "<span>Permit-required".

Reason:

A permit-required is the confined space in which normal hazards are presented plus other hazards. Its not option B because the answer would not be hazard because there talking about additional hazards and confined spaces (probably safe rooms). Its also not option C because characteristic is a type but its describing a type of hazard its not a way to confine it.

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
</span>
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A couple plans to have a child. the mother is homozygous for an autosomal recessive mutation. the father is heterozygous for the
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<u>Answer</u>:

  • The possible genotypes of the children are Hh and hh.
  • The probability of genotype Hh = 1/2
  • The probability of genotype hh = 1/2

<u>Explanation</u>:

  • <em>Autosomal genes</em> are the genes present on any of the chromosomes except the sex chromosomes.
  • An autosomal recessive mutation is the mutation in an autosomal gene which only expresses itself in the phenotype in homozygous condition and affects both males and female equally.
  • For the given question, let the autosomal gene be represented by H (dominant) and h (recessive)
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Since the <em>mother</em> is homozygous her genotype would be hh and the <em>father</em> is heterozygous so his genotype would be Hh.

The following cross is made to know the genotypes of the children :

hh X Hh--------> Hh Hh hh hh

So the <em>possible genotypes of the children are Hh and hh as shown in the cross. </em>

Note : An image is attached representing the cross in a Punnett square.

  • The probability of an event = No. of favourable outcomes/total no. of outcomes

The probability of occurrence of genotype Hh would be = 2/4 = 1/2

Similarly, the probability of occurrence of genotype hh would be 2/4 = 1/2



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