There are 6 different combinations of 2 books from the group of 4 that he could choose to do.
Let's say all of the books were letters.
Books a, b, c, and d.
Different combinations include:
ab, ac, ad, bc, bd, and cd.
'Vertex form', having just googled it, is another name for completing the square, which I have done extensively at school. This involved converting:
f(x) = ax^2 + bx + c --> f(x) = a(x-b)^2 + c
In the completed-square form, (b, c) are the co-ordinates of the vertex (which is the maximum/minimum point). So for part a:
- Here is the original
f(x) = x^2 + 12x + 11
- Halve the x-coefficient (the number before x) and use it as -b in the vertex form described above. You must then calculate the square of this number and minus it at the end because when you multiply it out, this is the surplus you will make along with x^2 + 12x:
f(x) = (x + 6)^2 - 36 + 11
- Tidy this up by collecting the constant (just number) terms together:
f(x) = (x + 6)^2 - 25
- Using the form a(x - b)^2 + c, we can work out that b = -6 (because -b = 6) and c = -25. This gives us the vertex (-6, -25) which is a minimum point because the graph is a positive quadratic, giving us the characteristing 'U' shape which has a bottom. If it were a negative quadratic (denoted by a negative x^2 coefficient), the vertex will be a maximum point because it has an 'n' shape instead.
- To solve the equation from here, make the function equal to zero:
(x + 6)^2 - 25 = 0
- Then take 25 to the other side:
(x + 6)^2 = 25
- Next, square-root both sides:
x + 6 = <span>±5
- Rearrange to finish:
x = -6 </span><span>± 5 = -1 or -11
- Therefore, the roots (solutions) to the equation x^2 + 12x + 11 = 0 are x = -1 or -11
This method will work the same for the other equations up there too, so I will leave them for you to do.
I hope this helps
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Answer: Choice A (yes it is a function; one range value exists for each domain value)
Put another way, each x corresponds to exactly one output only. We do not have any repeat x values. Any input you specify, there is only one output. If for example we had the two points (3,5) and (3,7) then the input x = 3 leads to multiple outputs y = 5 and y = 7 at the same time. This example is a non-function because of this. In this case, we don't have such repeated x values so that is why we have a function.
Try graphing out the four points given. You'll notice you cannot draw a vertical line through more than one point. Therefore, this graph passes the vertical line test. The vertical line test is to see if it's possible to draw a vertical line through more than one point on the graph. If so, then the relation fails to be a function.
(2+sqrt2i)^-1 = 1 / (<span>2+sqrt2i)</span>
