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3 years ago

Is -2.875 > -2 7/8?

Mathematics

1 answer:

natima [27]3 years ago

6 0

Answer

The statement is false

Step-by-step explanation:

When you convert either side to either a decimal or a fraction they end up equal. This means in order for the statement to be true it would have had to say greater than or equal to the other number or vice versa.

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Write a function to model the volume of a rectangular prism if the length is 24cm and the sum of the width and height is 16cm.

Salsk061 [2.6K]

24 plus 16 equals 40 is your answer <span />

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3 years ago

Cho hàm số (có đồ thị ) xác định và có đạo hàm tại , điểm thuộc đồ thị (C). Phương trình tiếp tuyến của đồ thị tại là

alexgriva [62]

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3 years ago

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Firlakuza [10]

Answer:

-3 i think because it is low i am soooo sorry if its wrong i really wasnt trying to get points i wanted to help hope for the best

Step-by-step explanation:

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3 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

3 years ago

According to government data, the probability that a woman between the ages of 25 and 29 was never married is 40%. in a random s

ddd [48]

The probability of finding 2 never married
10c2*0.4^2*0.6^8=
the probability of finding 1 never married
10C1*0.4*0.6^9=
the probability of finding 0 never married
10C0*0.6^10=

the answer is all the above answers added together.
think you can do the rest of the calculation by yourself. :)

btw nCr=n!/(n-r)!r!
good luck

3 0

3 years ago

Is -2.875 > -2 7/8? ​

Is -2.875 > -2 7/8?