Answer:
The BOD5 for this sample is 5 mg/L
Explanation:
The BOD5 takes into consideration the difference between the initial DO and the final DO divided by the fraction of the sample tested in a 300 mL BOD flask. The problem states that the sample was directly placed in a BOD bottle so we assume that the volume used was 300 mL of the water sample. The fraction of water is 1 (300/300).
BOD5 = (10-5)/1
BOD 5 = 5 mg/L
They are all forms of land movement i believe
Answer:
Find HJ, JK, and FG. HJ = EG or (100); HJ = 50. JK = EF or (60); JK = 30. HK or 40 = FG; FG = 80. AB = 10 and CD = 18
Explanation:
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Wind which is caused by uneven heating.
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