Answer:
A two-digit number can be written as:
a*10 + b*1
Where a and b are single-digit numbers, and a ≠ 0.
We know that:
"The sum of a two-digit number and the number obtained by interchanging the digits is 132."
then:
a*10 + b*1 + (b*10 + a*1) = 132
And we also know that the digits differ by 2.
then:
a = b + 2
or
a = b - 2
So let's solve this:
We start with the equation:
a*10 + b*1 + (b*10 + a*1) = 132
(a*10 + a) + (b*10 + b) = 132
a*11 + b*11 = 132
(a + b)*11 = 132
(a + b) = 132/11 = 12
Then:
a + b = 12
And remember that:
a = b + 2
or
a = b - 2
Then if we select the first one, we get:
a + b = 12
(b + 2) + b = 12
2*b + 2 = 12
2*b = 12 -2 = 10
b = 10/2 = 5
b = 5
then a = b + 2= 5 + 2 = 7
The number is 75.
And if we selected:
a = b - 2, we would get the number 57.
Both are valid solutions because we are changing the order of the digits, so is the same:
75 + 57
than
57 + 75.
Answer:
210 cm²
Step-by-step explanation:
The net of the right trapezoidal prism consists of 2 trapezoid base and four rectangles.
Surface area of the trapezoidal prism = 2(area of trapezoid base) + area of the 4 rectangles
✔️Area of the 2 trapezoid bases:
Area = 2(½(a + b)×h)
Where,
a = 7 cm
b = 11 cm
h = 3 cm
Plug in the values
Area = 2(½(7 + 11)×3)
= (18 × 3)
Area of the 2 trapezoid bases = 54 cm²
✔️Area of Rectangle 1:
Length = 6 cm
Width = 3 cm
Area = 6 × 3 = 18 cm²
✔️Area of Rectangle 2:
Length = 7 cm
Width = 6 cm
Area = 7 × 6 = 42 cm²
✔️Area of Rectangle 3:
Length = 6 cm
Width = 5 cm
Area = 6 × 5 = 30 cm²
✔️Area of Rectangle 4:
Length = 11 cm
Width = 6 cm
Area = 11 × 6 = 66 cm²
✅Surface area of the trapezoidal prism = 54 + 18 + 42 + 30 + 66 = 210 cm²
Answer:
I think its C im not really sure
Answer: 53.13
Explanation of answer: since theta is the unknown, then you must use the inverse of sin. (Which is sin with -1 subscript) I used a calculator and used inverse of sin and put 4/5 in parenthesis
