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padilas [110]
3 years ago
14

7. Use the following figure to answer questions a-d.

Mathematics
1 answer:
kati45 [8]3 years ago
4 0
B. 67
C. 43

Answer!!!!!!!!!!!!!!!!!!!
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What can each term of the equation be multiplied by to eliminate the fractions before solving? 1/2 x – 5/4 + 2x =5/6 + x
Karo-lina-s [1.5K]

The <u>equation</u>

\dfrac{1}{2}x-\dfrac{5}{4}+2x=\dfrac{5}{6}+x

consists of five <u>terms</u>, three of them contain <u>fractions.</u> The <u>denominators</u> of these fractions are 2, 4 and 6.

Find the LCM(2,4,6). Since

  • 2=2;
  • 4=2·2;
  • 6=2·3,

then LCM(2,4,6)=2·2·3=12.

Thus, you have to multiply each term of the equation by 12 to eliminate the fractions.

Answer: 12


8 0
4 years ago
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A city pool has 3 wading pools. Each pool is in the shape of a parallelogram with a
Vikki [24]

Answer:

i think it's 13.44

Step-by-step explanation:

im not really sure, but let me know if im wright pls!!

hope this helped!!

6 0
3 years ago
I’ll give brainliest IF ITS AN ACRUAL ANSWER, ALL USELESS ONES WILL BE REPORTED
Llana [10]

Answer:

C

Step-by-step explanation:

pls mark brainliest

multiply the numerator and denominator by the same number so, that all the fractions have a denominator of 12.

4 0
4 years ago
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A camera shop stocks eight different types of batteries, one of which is type A76. Assume there are at least 31 batteries of eac
Sauron [17]

Answer: 12,620,256

Step-by-step explanation:

Given: The camera shop socks eight different types of batteries and there re at least 31 batteries of each type.

Here we want to select r= 31 batteries from n= 8 kinds of batteries, then formula we use to find number of ways is ^{n+r-1}C_r=\ ^{31+8-1}C_{31}

=^{38}C_{31}=\dfrac{38!}{31!(38-31)!}\\\\=\dfrac{38!}{31!7!}\\\\=\dfrac{38\times37\times36\times35\times34\times33\times32\times31!}{31!\times5040}\\\\=12620256

Hence, the number of ways can a total inventory of 31 batteries be distributed among the eight different types = 12,620,256

3 0
3 years ago
What is the sum? (g2 – 4g4 + 5g + 9) + (–3g3 + 3g2 – 6)
levacccp [35]
<span>B. –4g4 – 3g3 + 4g2 + 5g + 3</span>

Hope it helped!
4 0
4 years ago
Read 2 more answers
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