If 2a^2+3^1a-5a^2, then a-a^2=

1 answer:

4 0

$Let's\ 2a^2+3a-5a^2=x\\\\then\\\\2a^2+3a-5a^2=x\\(2a^2-5a^2)+3a=x\\-3a^2+3a=x\\3a-3a^2=x\\3(a-a^2)=x\ \ \ |:3\\\\\boxed{a-a^2=\dfrac{x}{3}}$

$a-a^2\ \text{is 3 times smaller than}\ 2a^2+3a-5a^2$

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