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vovangra [49]
3 years ago
14

Find a sample size for which the median will always equal one of the values in the sample

Mathematics
1 answer:
irina [24]3 years ago
4 0

Answer:

Any odd sample size, larger than 1.

Step-by-step explanation:

We use the median to find the "middle" value of a sample, that is, the value separating the lower half from the upper half of the sample.

If the size of the sample is even

1,2,3,4

Both the upper half and the lower half should have the same size.

In this case, it is not possible to select only one value which respects this condition. So the mean between 2 and 3 = 2.5 is calculated. This value is not part of the sample.

If the size of the sample is odd

1,2,3,4,5

For a n-sized sample, with n odd, the median is the value at the position (n+1)/2. So her, it is 3, the value at the third position. In this case, it is always going to be an element at a position in the sample, that is, an element of the sample.

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A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the
Svetlanka [38]

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The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be x.

And the hotel charge in second city before tax be y.

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

y=x-1500   ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of x + 10% of y = $670.

\frac{6x}{100} +\frac{10y}{100} =670

0.06x+0.10y=670

Substituting the value of y from equation (1) we get:

0.06x+0.10(x-1500)=670

0.06x+0.10x-150=670

0.16x-150=670

<em>Adding both sides by 150 we get:</em>

0.16x=820

<em>Dividing both sides by 0.16 we get:</em>

x=5125.

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of x in equation (1) we get:

y=x-1500

y=5125-1500

y=3625.

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0
4 years ago
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