What is the proportional numbers of 26/13

makvit [3.9K]

Answer:

6

Step-by-step explanation:

You are looking for the cross section of ask three circles. This is true for the smallest part, with the number 6 in it.

5 0

3 years ago

Find the slope (-2,-4) (2,4)

Alex

Answer:

8 over 4

Step-by-step explanation:

5 0

3 years ago

Finding the roots (zeros)

GenaCL600 [577]

Answer:

1.5 + 1.3228756555323i

1.5 - 1.3228756555323i

Step-by-step explanation:

y = ax^2 + bx + c

a = 1, b = -3, c = 4

Using the quadractic formula:

$\frac{-b±\sqrt{b^2-4ac} }{2a} \\\\= \frac{3±\sqrt{9-4(1)(4)}}{2(1)}\\\\= \frac{3±2.64i}{2}\\\\= 1.5 ± 1.32$

Note: Kindly ignore the A in the above solution ^

Hence, there is no real solution. It has complex roots.

<em>Feel free to mark this as brainliest! :D</em>

4 0

3 years ago

What is 85% of 21?<br> I need to know for school because we're doing this project.

mylen [45]

Answer:

85% of 21 is 17.85.

5 0

2 years ago

Read 2 more answers

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:

Vikentia [17]

Answer:

a

$\= x = 18.5$ , $\sigma = 5.15$

b

$15.505 < \mu < 21.495$

c

$14.93 < \mu < 22.069$

Step-by-step explanation:

From the question we are are told that

The sample data is 21, 14, 13, 24, 17, 22, 25, 12

The sample size is n = 8

Generally the ample mean is evaluated as

$\= x = \frac{\sum x }{n}$

$\= x = \frac{ 21 + 14 + 13 + 24 + 17 + 22+ 25 + 12 }{8}$

$\= x = 18.5$

Generally the standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum (x- \=x )^2}{n}}$

$\sigma = \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}$

$\sigma = 5.15$

considering part b

Given that the confidence level is 90% then the significance level is evaluated as

$\alpha = 100-90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.645$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.645 * \frac{5.15 }{\sqrt{8} }$

=> $E = 2.995$

The 90% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 2.995 < \mu < 18.5 + 2.995$

$15.505 < \mu < 21.495$

considering part c

Given that the confidence level is 95% then the significance level is evaluated as

$\alpha = 100-95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.96 * \frac{5.15 }{\sqrt{8} }$

=> $E = 3.569$

The 95% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 3.569 < \mu < 18.5 + 3.569$

$14.93 < \mu < 22.069$

8 0

3 years ago