I think it is the second option
<h3>
Answers: x = 30 and y = 150</h3>
============================================================
Explanation:
For any cyclic quadrilateral (aka inscribed quadrilateral), the opposite angles are always supplementary.
One pair of such angles is A and C
A+C = 180
x+y = 180 is one equation to form
The other pair of supplementary angles is B and D
B+D = 180
y-45+2x+15 = 180
2x+y-30 = 180
2x+y = 180+30
2x+y = 210 is the other equation to form
--------------
So the system of equations we have is
![\begin{cases}x+y = 180\\2x+y = 210\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7Dx%2By%20%3D%20180%5C%5C2x%2By%20%3D%20210%5Cend%7Bcases%7D)
Both equations involve 'y', with the same coefficient, so we can subtract straight down to eliminate this variable.
- The x terms subtract to x-2x = -x
- The y terms subtract to y-y = 0y = 0, so the y terms go away
- The right hand sides subtract to 180-210 = -30
We end up with -x = -30 which solves to x = 30
--------------
Once we know x, we can determine y by plugging it into any equation involving x,y and solving for y
Let's say we picked on the first equation
x+y = 180
30+y = 180
y = 180-30
y = 150
Or we could pick on the second equation
2x+y = 210
2(30) + y = 210
60+y = 210
y = 210-60
y = 150
Only one equation is needed. However, doing both like this shows that we get the same y value, and it helps confirm the answers.
Answer
102.1
Step-by-step explanation:
area <em> </em><em>of </em><em>the</em><em> </em><em>shaded</em><em> </em><em>region</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>area</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>the </em><em>whole</em><em> </em><em>circle</em><em> </em><em>subt</em><em>ract</em><em> </em><em>area</em><em> </em><em>area</em><em> </em><em>of</em><em> </em><em>the </em><em>unshaded</em><em> </em><em>minor</em><em> </em><em>segm</em><em>ent</em><em>.</em>
All you have to do is plug in the tables to T. Since there's 5 tables, your new equation will be C=4x5+2. Then, you solve using pemdas.
C=4x5+2.
C=20+2
C=22
You need 22 chairs.