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3 years ago

PLZ HELP, GIVING BRAINLIEST!!

Mathematics

1 answer:

RSB [31]3 years ago

3 0

Sine of theta equals to the ratio of the magnitude/length of the adjacent side with 3 inches over the magnitude/length of the hypotenuse being 5 inches. Sine of theta, therefore, is three divided by 5 which is 0.6.

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Using the order of operations, what should be done first to evaluate 6 squared + 10 divided by (negative 5) (3) minus 5?

tiny-mole [99]

If anything is in parentheses do that first, however if there isn’t you always do exponents next so evaluate 6 squared
Hope this helps!!

3 0

4 years ago

Read 2 more answers

Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

Ratling [72]

Answer: point estimate = 3.88

Margin of error = 0.63

Step-by-step explanation:

Confidence interval is written in the form,

(Point estimate - margin of error, Point estimate + margin of error)

The sample mean, x is the point estimate for the population mean. Let m represent the margin of error. Since the confidence interval is given as (3.25 , 4.51), it means that

x - m = 3.25

x + m = 4.51

Adding both equations, it becomes

2x = 7.76

x = 7.76/2

x = 3.88

Substituting x = 3.88 into x + m = 4.51, it becomes

3.88 + m = 4.51

m = 4.51 - 3.88

m = 0.63

8 0

3 years ago

Determine the numerical length of JK.

Zarrin [17]

Answer:

So the two sectors add to the full length:

JK + IJ = IK

x+6 + 9 = 2x

Rearrange:

x=15

So the numerical length:

2*15

5 0

3 years ago

Read 2 more answers

Ahorras $15 por semana para comprar una de las bicicletas mostradas.

jeka94

Answer:

yo ocupo la misma respuestas

Step-by-step explanation:

la tienes o q? soy de higschool Ossining

7 0

3 years ago

Please can someone help me with this question

sasho [114]

Answer:

r = - $\frac{6a}{1-5m^2}$

Step-by-step explanation:

Rewrite the equation as $\sqrt{x} 6a+r/5r$ = m

Remove the radical on the left side of the equation by squaring both sides of the equation.

( $\sqrt{\frac{6a+r}{5r} )^{2}$ = m^2

Then, you simplify each of the equation.

Rewrite: ( $\sqrt{\frac{6a+r}{5r} )^{2}$ as $\frac{6a+r}{5r} = m^{2}$

Remove any parentheses if needed.

Solve for r.

Multiply each term by r and simplify."

Multiply both sides of the equation by 5.

6a+r= m^2r⋅(5)

Remove parentheses.

Move 5 to the left of (m ^2) r

6a+r=5m^2)r

Subtract 5m^2)r from both sides of the equation.

6a+r-5m^2)r=0

Subtract 6a from both sides of the equation.

r-5m^2)r=-6a

Factor r out of r-5m^2)r

r(1-5m^2)=-6a

Divide each term by 1-5m^2 and simplify.

r = - $\frac{6a}{1-5m^2}$

There you go, hope this helps!

4 0

4 years ago