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77julia77 [94]
3 years ago
11

In one type of dog, black spots (B) are dominant over brown spots (b) and long tails (L) are dominant over short tails (l). Use

the dihybrid cross for parents with the genotypes BBLl and BbLl and determine the likelihood of offspring with the phenotype of brown spots and short tails.
BL Bl BL Bl
BL BBLL BBLl BBLL BBLl
Bl BBLl BBll BBLl BBll
bL BbLL BbLl BbLL BbLl
bl BbLl Bbll BbLl Bbll
0%
10%
20%
50%
Biology
2 answers:
stiks02 [169]3 years ago
8 0

Answer:

There is a 0% chance of getting the phenotype of brown spots and short tails.

Explanation:

Here is a Punnett square

             BL              Bl              BL               Bl

BL       BBLL          BBLl          BBLL          BBLL

Bl        BBLl            BBll           BBLl           BBll

bL       BbLL           BbLl          BbLL          BbLl

bl        BbLl            Bbll            BbLl          Bbll

Irina18 [472]3 years ago
6 0

Answer:

Option A, 0%

Explanation:

It is given that

a) black spots (B) are dominant over brown spots (b)

b) long tails (L) are dominant over short tails (l)

Thus, the offspring with genotype "bb" will be of brown color as b is a recessive trait.

Also, offspring with genotype "ll" will have short tail as short tail is a recessive trait.

Thus, in the given punnet square genotype representing brown color and short tail together are - zero

Thus, option A is correct.

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