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MrRissso [65]
3 years ago
11

Someone please help me !

Mathematics
1 answer:
Gwar [14]3 years ago
4 0
30 = arc BC / 2
arc BC = 2(30)
arc BC = 60

answer
D. 60
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F(x) = x-5, g(x) =x^2 - 1 find (f+g)
DaniilM [7]
F(x)=x-5
g(x)=x^2
Now adding f(x) and g(x)
x-5+x^2-1
x^2+x-6
x^2+(3-2)x-6
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x(x+3)-2(x+3)
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2 years ago
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tatuchka [14]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
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A building is 2ft from a 7 ft fence that surrounds the property. A worker wants to wash a window in the building 11ft from the g
777dan777 [17]

Answer:


Step-by-step explanation:

plug the numbers into the Pythagorean theorem

which is A^2 + B^2 = C^2

4 0
2 years ago
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Newborn males have weights with a mean of 3272.8 g and a standard deviation of 660.2 g. Newborn females have weights with a mean
Maksim231197 [3]

The correct option is:   a female who weighs 1500 g

<em><u>Explanation</u></em>

<u>Formula for finding the z-score</u> is:  z= \frac{X-\mu}{\sigma}

Newborn males have weights with a mean(\mu) of 3272.8 g and a standard deviation(\sigma) of 660.2 g.

So, the z-score for the newborn male who weighs 1500 g will be.......

z(X=1500)=\frac{1500-3272.8}{660.2}=-2.685... \approx -2.69

According to the normal distribution table,  P(z=-2.69)=0.0036 = 0.36\%

Now, newborn females have weights with a mean(\mu) of 3037.1 g and a standard deviation(\sigma) of 706.3 g.


So, the z-score for the newborn female who weighs 1500 g will be.......

z(X=1500)=\frac{1500-3037.1}{706.3}=-2.176... \approx -2.18

According to the normal distribution table,  P(z=-2.18)=0.0146 = 1.46\%

As we can see that the <u>probability that a newborn female has weight of 1500 g is greater than newborn male</u>,  so a newborn female has the weight of 1500 g that is more extreme relative to the group from which he came.

5 0
2 years ago
What is the value of A when we rewrite... (PLZ HELP QUICK)
Marina86 [1]

Answer:

<h2>\frac{133}{8}</h2>

Step-by-step explanation:

Given,

{( \frac{5}{2} )}^{x}  +  {( \frac{5}{2} )}^{x + 3}

=  {( \frac{5}{2}) }^{x}  +  {( \frac{5}{2}) }^{x}  \times  {( \frac{5}{2} )}^{3}

= ( \frac{5}{2} ) ^{x} (1 +  {( \frac{5}{2} )}^{3}

=  {( \frac{5}{2} )}^{x} (1 +  \frac{125}{8} )

=  {( \frac{5}{2} )}^{x} ( \frac{1 \times 8 + 125}{8} )

=  {( \frac{5}{2}) }^{x} ( \frac{8 + 125}{8} )

{( \frac{5}{2} )}^{x} ( \frac{133}{8} )

Comparing with A • {( \frac{5}{2}) }^{x}

A = \frac{133}{8}

Hope this helps...

Good luck on your assignment...

7 0
3 years ago
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