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3 years ago

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Someone please help me !

1 answer:

Gwar [14]3 years ago

4 0

30 = arc BC / 2
arc BC = 2(30)
arc BC = 60

answer
D. 60

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F(x) = x-5, g(x) =x^2 - 1 find (f+g)

DaniilM [7]

F(x)=x-5
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Now adding f(x) and g(x)
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2 years ago

tatuchka [14]

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Step-by-step explanation:

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3 years ago

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A building is 2ft from a 7 ft fence that surrounds the property. A worker wants to wash a window in the building 11ft from the g

777dan777 [17]

Answer:

Step-by-step explanation:

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2 years ago

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Newborn males have weights with a mean of 3272.8 g and a standard deviation of 660.2 g. Newborn females have weights with a mean

Maksim231197 [3]

The correct option is: a female who weighs 1500 g

<em><u>Explanation</u></em>

<u>Formula for finding the z-score</u> is: $z= \frac{X-\mu}{\sigma}$

Newborn males have weights with a mean $(\mu)$ of 3272.8 g and a standard deviation $(\sigma)$ of 660.2 g.

So, the z-score for the newborn male who weighs 1500 g will be.......

$z(X=1500)=\frac{1500-3272.8}{660.2}=-2.685... \approx -2.69$

According to the normal distribution table, $P(z=-2.69)=0.0036 = 0.36\%$

Now, newborn females have weights with a mean $(\mu)$ of 3037.1 g and a standard deviation $(\sigma)$ of 706.3 g.

So, the z-score for the newborn female who weighs 1500 g will be.......

$z(X=1500)=\frac{1500-3037.1}{706.3}=-2.176... \approx -2.18$

According to the normal distribution table, $P(z=-2.18)=0.0146 = 1.46\%$

As we can see that the <u>probability that a newborn female has weight of 1500 g is greater than newborn male</u>, so a newborn female has the weight of 1500 g that is more extreme relative to the group from which he came.

5 0

2 years ago

What is the value of A when we rewrite... (PLZ HELP QUICK)

Marina86 [1]

Answer:

<h2> $\frac{133}{8}$ </h2>

Step-by-step explanation:

Given,

${( \frac{5}{2} )}^{x} + {( \frac{5}{2} )}^{x + 3}$

$= {( \frac{5}{2}) }^{x} + {( \frac{5}{2}) }^{x} \times {( \frac{5}{2} )}^{3}$

$= ( \frac{5}{2} ) ^{x} (1 + {( \frac{5}{2} )}^{3}$

$= {( \frac{5}{2} )}^{x} (1 + \frac{125}{8} )$

$= {( \frac{5}{2} )}^{x} ( \frac{1 \times 8 + 125}{8} )$

$= {( \frac{5}{2}) }^{x} ( \frac{8 + 125}{8} )$

${( \frac{5}{2} )}^{x} ( \frac{133}{8} )$

Comparing with A • ${( \frac{5}{2}) }^{x}$

A = $\frac{133}{8}$

Hope this helps...

Good luck on your assignment...

7 0

2 years ago