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DerKrebs [107]
3 years ago
5

What is one way in which fission differs from fusion?

Biology
2 answers:
AVprozaik [17]3 years ago
8 0

Answer: Option (A) is the correct answer.

Explanation:

Nuclear fission is a process in which a heavy radioactive nucleus splits into two or more smaller nuclei.

For example, ^{235}_{92}U + ^{1}_{0}n \rightarrow ^{236}_{92}U\rightarrow ^{92}_{36}Kr + ^{141}_{56}Ba + 3^{1}_{0}n is a nuclear fission reaction.

Whereas in a nuclear fusion reaction two small nuclei combine together to result in the formation of a heavy nuclei.

For example, ^{2}_{1}H + ^{3}_{1}H \rightarrow ^{4}_{2}He + ^{1}_{0}n + Energy

Thus, we can conclude that one way in which fission differs from fusion is that fission splits nuclei, fusion combines nuclei.  

sleet_krkn [62]3 years ago
6 0
<span>A) Fission splits nuclei, fusion combines nuclei. </span>
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5. Think Critically Suppose you are pulling a wagon with
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3 years ago
In a population of 150 toads, poisonous (P) is dominant over non-poisonous (p). According to the Hardy-Weinberg equation, the ex
aalyn [17]

Answer: Χ²=8.18

Explanation: In this population, the frequency of homozygote poisonous toads is:

p^{2} =\frac{100}{150}

p^{2} = 0.667

p = \sqrt{0.667}

p=0.82

For the homozygote non-poisonous toads:

q^{2} = \frac{5}{150}

q^{2} =0.034

q = \sqrt{0.034}

q = 0.18

The frequency for heterozygote poisonous toad, we can use the Hardy-Weinberg equation: p^{2} + 2pq + q^{2} = 1, in which, heterozygote frequency is given by 2pq

2pq = 2*0.82*0.18 = 0.3

Now, to compute the chi-square test, follow the instructions:

1) Find the observed values: in this case, they are the found frequency:

0.82       0.3         0.18

2) Find the expected values: As the question mentioned, the expected proportion is:

16            8             1

3) Subtract the observed value from the expected value:

0.82 - 16 = - 0.184          0.3 - 8 = -7.7             0.18 - 1 = - 0.818

4) Square each value from above:

(-0.184)² = 0.034            (-7.7)² = 59.3                 (-0.818)² = 0.77

5) Divide each value by expected value:

\frac{0.034}{16} = 0.0021                   \frac{59.3}{8} = 7.41                      \frac{0.77}{1} = 0.77

6) Add all the values and we will have the chi-square test:

Χ² = 0.0021 + 7.41 + 0.77 = 8.18

The chi-square test is Χ² = 8.18

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4 years ago
In which order are the steps of the scientific method commonly listed?
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