We have to use limits to find the area of the region bounded by the graph $f(x) = 4 - 2x^{3}$ , the x-axis, and the vertical lines x=0 and x=1.

So, the area will be

A = $\int\limits^1_0 {(4 - 2x^{3})} \, dx$

= $[4x - \frac{x^{4}}{2} ]^{1} _{0}$

= $4 - \frac{1}{2}$

= $\frac{7}{2}$ square units. (Answer)

3 0

3 years ago

Parallel lines m and n are cut by a transversal t. Which two angles are NOT corresponding angles?

Alex787 [66]

1 and 6 are not corresponding angles. They have different degrees. hope this helps :)

6 0

3 years ago

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Factor p 2 - 8p - 20.

Helga [31]

Answer is -2(3p+10)

hope this helps :)

8 0

3 years ago

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What number increased by 15% equal 161

kkurt [141]

Answer:

100%+15% = 115%

proportionally:

x - 100%

161 - 115%

x = (161 * 100%) / 115% = 140

4 0

3 years ago

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