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3 years ago

Find two consecutive even integers whose sum is 14

1 answer:

5 0

Let x = small number
Let y = large number
Because they are consecutive even numbers,they must have a difference of 2:
y-x=2
y=2+x

Eqn 1: x+(2+x)=14

Eqn 2: x(2+x)=48

2x+2=14
2x=12
x=6

This means y must be 8

so your two numbers are 6 and 8

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Step-by-step explanation:

Probability is commonly known as the chance of success of a particular event. The probability of failure of the event can also be estimated.

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(b) Probability of having type 1 and 2 defects is: $P(A_{1} n A_{2}) = P(A_{1}) + P(A_{2}) - P(A_{1}U A_{2}) = 0.12 + 0.07 - 0.13 = 0.06$

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3 years ago

The sum of the two numbers is 40 and the difference is 6. What are the numbers?

natita [175]

Answer:

17 + 23 = 40

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$p(b \: and \: g) = \frac{5}{16} \times \frac{1}{5} = \frac{1}{16}$

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