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Nezavi [6.7K]
3 years ago
5

Find two consecutive even integers whose sum is 14

Mathematics
1 answer:
bagirrra123 [75]3 years ago
5 0
Let x = small number
Let y = large number 
Because they are consecutive even numbers,they must have a difference of 2:
y-x=2
y=2+x

Eqn 1: x+(2+x)=14

Eqn 2: x(2+x)=48

2x+2=14
2x=12
x=6

This means y must be 8 

so your two numbers are 6 and 8 
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The sum of two numbers is 21. Three times the larger is equal to four times the smaller.
MatroZZZ [7]
Answer x = 12 and y = 9
Step by step
First identify the equations
The sum of two numbers is 21
x + y = 21
Change to y intercept for ease of math
y = 21 - x ( call this equation a)
Three times the larger is equal to four times the smaller
3x = 4y (call this equation b)
Now substitute the value of y = 21 -x into equation b
3x = 4(21-x)
Distribute
3x = 84 - 4x
Now we want to isolate x by adding 4x to each side
3x + 4x = 84 -4x + 4x
Combine like terms
7x = 84
Now solve for x by dividing both sides by 7
x = 12

Now to find y
Using equation a from above
y = 21 - x
Substitute our x value of 12 into equation
y = 21 - 12
solve for y
y = 9
Now check your work
x = 12 and y = 9
The sum of two numbers is 21
12 + 9 = 21

Three times the larger (x) is equal to four times the smaller (y)
3x12 = 4x9
36 = 36
Problem solved!!
8 0
1 year ago
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