Hey there!!
Shape given - Cylinder
In order to find the amount of gas the vessel can hold, we will have to find the volume of the cylindrical vessel.
How do we find the volume of a cylindrical vessel?
The formula : πr²h
Where ' r ' is the radius and ' h ' is the height.
The height is given by 9 feet.
The diameter is given by 6 feet. This is the tricky part, we will have to use the radius not the diameter.
The diameter = Radius + Radius
6 = radius + radius
6 = 2 × radius
Dividing 2 on both sides
6 ÷ 2 = radius
Hence, the radius is 3 feet.
We have :
Height = 9 feet
Radius = 3 feet
Volume : π ( 3 )² ( 9 )
... π × 9 × 9
... π × 81
... 3.14 × 81
... 254.34 feet³
Hence, the amount could be held in the cylindrical is 254.34
Hope my answer helps!!
Answer:
k<0 or k>4
Step-by-step explanation:
In the generic equation ax² + bx + c = 0, there are two solutions only if discriminant D>0 where D = b²-4ac.
Mapping your equation on the generic means that:
a = k
b = k
c = 1
So when we have to solve D>0 we solve:
k² - 4k > 0
k(k-4) > 0
roots are k=0 and k=4
k² - 4k > 0 when k<0 or k>4
Answer:
n = -5
Step-by-step explanation:
-6(-5n+3)+2=-166
distribute the -6
- 6 * -5n = 30n
-6 * 3 = - 18
30n - 18 + 2 = -166
combine like terms
30n - 16 = -166
add 16 to both sides
30n = -150
divide both sides by 30
30n/30=n
-150/30=-5
we're left with n = -5
15 divided by 3 = 5 equal groups