Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
Answer:
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Answer:
5x+3>4x+7
-4x -4x
x+3>7
-3 -3
x>4
so the answer will be the second
Step-by-step explanation:
Hello :
the nth term ( general term of an arithmetic sequence is :
An =A1+(n-1)d ....a common difference is : d , A1 : the first terme
A1 = 5 and : d = 1 - 5 = - 4 n = 21
A21 = 5 + (21 -1)(-4)
A21 = 5 - 80 = -75
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