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mariarad [96]
3 years ago
6

How many 2-digit numbers can be formed from the digits 1 through 8 if each digit is only used once?

Mathematics
2 answers:
SVEN [57.7K]3 years ago
6 0

Answer:

56.

Step-by-step explanation:

That is the number of permutations of 2 from 8

= 8P2

= 8!/(8-2)!

= 8!/6!

= 8 * 7

= 56.

S_A_V [24]3 years ago
5 0

Answer:57

Step-by-step explanation:

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..

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Learn more,

brainly.com/question/4397150

8 0
3 years ago
Marina correctly simplified the expression (-4a^-2 b^4)/(8a^-6b^-3) assuming that a does not equal 0 and b does not equal 0. Her
Elza [17]
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