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vitfil [10]
3 years ago
14

The ordered pairs on the graph represent a proportional relationship. What is the constant proportionality of Y to X

Mathematics
1 answer:
castortr0y [4]3 years ago
7 0
A 7/4 because the slope of the line is 7/4
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iragen [17]

Answer:

first is a second is d

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Given the following diagram, find the missing measure.
madam [21]

m3 = 110°

Step-by-step explanation:

m1 = 180° - m4 ( sum of angles in a straight angle )

m1 = 180° - 150° = 30°

m3 = 180° - (m2 + m1) ← sum of angles in a triangle

m3 = 180° - (40 + 30 )° = 180° - 70° = 110°

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2 years ago
It is asking what is the relationship between segment pq and p”q’
nadezda [96]

angles it sounds like but ik the struggle

7 0
3 years ago
Suppose Wesley is a marine biologist who is interested in the relationship between the age and the size of male Dungeness crabs.
Eva8 [605]

Answer:

20.24 cm

Step-by-step explanation:

Here, since the age of the crab is given in months and the regression line was computed using the age in months, we just have to replace the value of the age in the formula to estimate the size.

The formula obtained for the estimated size Y was

Y = 9.1411 + 0.4775X  

where X is the age in months

Replacing X with 23.2417, we get

Y = 9.1411 + 0.4775*23.2417 = 20.24 cm

7 0
3 years ago
From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s
Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

60 out of 100 scores are passing scores, hence n = 100, \pi = \frac{60}{100} = 0.6

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0
2 years ago
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